If a steel coil weighs 8,000 pounds, how much securement is required to prevent forward movement?

Prepare for the New York Metal Coil Endorsement Test. Utilize flashcards and multiple choice questions, each with hints and explanations. Ace your exam!

To determine the securement required to prevent forward movement of a steel coil weighing 8,000 pounds, it's crucial to understand the principles of load securement and the specific regulations that apply, such as those articulated by the Federal Motor Carrier Safety Administration (FMCSA).

In this case, the required securement is calculated based on a fraction of the load's weight, taking into account factors such as the type of cargo and the conditions under which it will be transported. For forward movement prevention, the general standard requires securement to be at least one-half of the weight of the cargo, unless otherwise specified.

Since the steel coil weighs 8,000 pounds, the securement calculation is as follows:

  • One-half of the weight: 8,000 pounds ÷ 2 = 4,000 pounds.

However, to ensure sufficient securement, regulations often recommend securing the load to a higher standard, generally around 80%. This means that to effectively prevent forward movement, the securement required would be approximately:

  • 8,000 pounds (total weight) x 0.80 (80%) = 6,400 pounds.

Thus, the 6,400 pounds indicated as the correct securement weight provides a protective buffer to

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